10=90(b^2)

Solution for 10=90(b^2) equation:

10=90(b^2)

We move all terms to the left:

10-(90(b^2))=0

determiningTheFunctionDomain
-90b^2+10=0

a = -90; b = 0; c = +10;
Δ = b2-4ac
Δ = 02-4·(-90)·10
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*-90}=\frac{-60}{-180}
=1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*-90}=\frac{60}{-180}
=-1/3
$